50^2+x^2=60^2

Solution for 50^2+x^2=60^2 equation:

50^2+x^2=60^2

We move all terms to the left:

50^2+x^2-(60^2)=0

We add all the numbers together, and all the variables

x^2-1100=0

a = 1; b = 0; c = -1100;
Δ = b2-4ac
Δ = 02-4·1·(-1100)
Δ = 4400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4400}=\sqrt{400*11}=\sqrt{400}*\sqrt{11}=20\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{11}}{2*1}=\frac{0-20\sqrt{11}}{2}
=-\frac{20\sqrt{11}}{2}
=-10\sqrt{11}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{11}}{2*1}=\frac{0+20\sqrt{11}}{2}
=\frac{20\sqrt{11}}{2}
=10\sqrt{11}
$